Begginer

## If f : R → R and g : R → R defined by f(x) = 2x + 3 and g(x) = x2 + 7, then the value of x for which f(g(x)) = 25 is

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If f : R → R and g : R → R defined by f(x) = 2x + 3 and g(x) = x2 + 7, then the value of x for which f(g(x)) = 25 is ...

Begginer

## Let f : N → R : f(x) = (frac{(2 x-1)}{2}) and g : Q → R : g(x) = x + 2 be two functions. Then, (gof) ((frac{3}{2})) is

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Let f : N → R : f(x) = (frac{(2 x-1)}{2}) and g : Q → R : g(x) = x + 2 be two functions. Then, (gof) ((frac{3}{2})) is 1) 3 ...

Begginer

## If f : R → R, g : R → R and h : R → R are such that f(x) = x2, g(x) = tan x and h(x) = log x, then the value of (go(foh)) (x), if x = 1 will be

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If f : R → R, g : R → R and h : R → R are such that f(x) = x2, g(x) = tan x and h(x) = log x, then the value of ...

Begginer

## If the binary operation * is defind on the set Q+ of all positive rational numbers by a * b = (frac{a b}{4}). Then, (3 *left(frac{1}{5} * frac{1}{2}right)) is equal to

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If the binary operation * is defind on the set Q+ of all positive rational numbers by a * b = (frac{a b}{4}). Then, (3 *left(frac{1}{5} * frac{1}{2}right)) is equal to 1) (frac{3}{160}) ...

Begginer

## Let * be a binary operation on set Q of rational numbers defined as a * b = (frac{a b}{5}). Write the identity for *.

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Let * be a binary operation on set Q of rational numbers defined as a * b = (frac{a b}{5}). Write the identity for *. 1) 5 2) 3 3) 1 ...

Begginer

## For binary operation * defind on R – {1} such that a * b = (frac{a}{b+1}) is

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For binary operation * defind on R – {1} such that a * b = (frac{a}{b+1}) is 1) not associative 2) not commutative 3) commutative 4) both (a) and (b) ...