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Question 8: NCERT Solutions for 12th Class Physics: Chapter 5-Magnetism and Matter
A closely wound solenoid of 2000 turns and area of cross-section 1.6 × 10-4 m2, carrying a current of 4.0 A, is suspended through its centre allowing it to turn in a horizontal plane.
(a) What is the magnetic moment associated with the solenoid?
(b) What is the force and torque on the solenoid if a uniform horizontal magnetic field of 7.5 × 10-2 T is set up at an angle of 30° with the axis of the solenoid?
Solution:
(a) Magnetic moment associated with solenoid
M = NIA = 2000 × 4 × 1.6 × 10-4 = 1.28 A m2
(b) Force on the solenoid will be zero in uniform magnetic field.
Torque x = MB sinθ = 1.28 × 7.5 × 10-2 × sin 30° or × = 4.8 × 10-2 N m The torque tends to align the solenoid in the direction of magnetic field.
Check the complete chapter with solutions.
NCERT Solutions for 12th Class Physics: Chapter 5-Magnetism and Matter