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Question 35: NCERT Solutions for 12th Class Physics: Chapter 9-Ray Optics and Optical Instruments
(a) For the telescope described in previous question 34 (a), what is the separation between the objective and the eyepiece?
(b) If this telescope is used to view a 100 m tall tower 3 km away. What is the height of the image of the tower formed by the objective lens?
(c) What is the height of the final image of the tower if it is formed at 25 cm?
Solution:
(a) The separation between objective lens and the eyepiece can be calculated in both the conditions of most relaxed eye and most strained eye. Most relaxed eye L= ƒ0 + ƒe= 140 + 5 = 145 cm
Most strained eye object distance ‘ue‘ for eye lens
(b)
(c) Now we want to find the height of final image A”B” assuming it to be formed at 25 cm.
Check the complete chapter with solutions.
NCERT Solutions for 12th Class Physics: Chapter 9-Ray Optics and Optical Instruments