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Question 20: NCERT Solutions for 12th Class Physics: Chapter 3-Current Electricity

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Question 20: NCERT Solutions for 12th Class Physics: Chapter 3-Current Electricity

(a) Given n resistors each of resistance R, how will you combine them to get the

  • maximum
  • minimum effective resistance? What is the ratio of the maximum to minimum resistance?

(b) Given the resistances of 1 Ω, 2Ω, 3Ω, how will be combine them to get an equivalent resistance of

  • (11/3) Ω
  • (11/5) Ω,
  • 6 Ω,
  • (6/11) Ω?

(c) Determine the equivalent resistance of network shown in figure.

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1 Answer

  1. Solution:

    (a)

    • For maximum effective resistance, all the resistors should be joined in series. Rmmax = R + R + R+……..n or Rmax = nR
    • For minimum effective resistance, all the resistors should be joined in parallel.


    (b) All possible combinations with resistances 1 Ω, 2 Ω and 3 Ω are

    So, the combinations for the desired results can be selected.

    Check the complete chapter with solutions.

    NCERT Solutions for 12th Class Physics: Chapter 3-Current Electricity