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Question 14: NCERT Solutions for 12th Class Physics: Chapter 13-Nuclei
The nucleus
decays by β– emission. Write t down the β– decay equation and determine
r the maximum kinetic energy of the electrons emitted. Given that:
= 22.994466 amu,
= 22.989770 amu.
Solution:
The β– decay of
may be explained as
As
is massive, the kinetic energy released is mainly shared by electron-positron pair. When the neutrino carries no energy, the electron has a maximum kinetic energy equal to 4.374 MeV.
Check the complete chapter with solutions.
NCERT Solutions for 12th Class Physics: Chapter 13-Nuclei